Motion Mastery: Accelerated & Projectile Quiz

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Quiz on vertical, horizontal, and free-fall motion.

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Lyra Camile Gacayan

Filipinas

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Froggy Jumps Motion Mastery: Accelerated & Projectile QuizVersión en línea Quiz on vertical, horizontal, and free-fall motion. por Lyra Camile Gacayan 1 Which equation gives vertical displacement under constant acceleration? a s = u t - 1/2 a t^2 b s = ut + 1/2 a t^2 c v = u t + a t 2 In free fall near Earth, the acceleration is approximately: a 9.8 m/s^2 upward b 0 m/s^2 c 9.8 m/s^2 downward 3 Ideal projectile with no air resistance has horizontal acceleration: a 0 m/s^2 b g downward c 9.8 m/s^2 4 Time to return to launch height for vertical throw with speed u is: a u/g b 2g/u c 2u/g 5 In horizontal projectile motion with no air, which is true? a Horizontal velocity remains constant b Vertical velocity remains constant c Total speed is constant 6 Vertical velocity under constant acceleration is given by: a v_y = v0_y + g t b v_y = g t^2 c v_y = v0 + a t^2 7 For a dropped object, speed after t seconds is: a v = g t b v = 1/2 g t^2 c v = t/g 8 From a height, horizontal launch: which is true? a Total speed is constant b Horizontal velocity is constant (no air resistance) c Vertical velocity is constant 9 Vertical time of flight from height h (drop) is: a t = sqrt(2h/g) b t = h/g c t = sqrt(g/2h) 10 Vertical displacement with initial vertical velocity v0 is: a y = v0 t + 1/2 g t^2 b y = 1/2 a t^2 only c y = v0 t

Froggy Jumps

Motion Mastery: Accelerated & Projectile QuizVersión en línea

Quiz on vertical, horizontal, and free-fall motion.

por Lyra Camile Gacayan

Which equation gives vertical displacement under constant acceleration?

s = u t - 1/2 a t^2

s = ut + 1/2 a t^2

v = u t + a t

In free fall near Earth, the acceleration is approximately:

9.8 m/s^2 upward

0 m/s^2

9.8 m/s^2 downward

Ideal projectile with no air resistance has horizontal acceleration:

0 m/s^2

g downward

9.8 m/s^2

Time to return to launch height for vertical throw with speed u is:

u/g

2g/u

2u/g

In horizontal projectile motion with no air, which is true?

Horizontal velocity remains constant

Vertical velocity remains constant

Total speed is constant

Vertical velocity under constant acceleration is given by:

v_y = v0_y + g t

v_y = g t^2

v_y = v0 + a t^2

For a dropped object, speed after t seconds is:

v = g t

v = 1/2 g t^2

v = t/g

From a height, horizontal launch: which is true?

Total speed is constant

Horizontal velocity is constant (no air resistance)

Vertical velocity is constant

Vertical time of flight from height h (drop) is:

t = sqrt(2h/g)

t = h/g

t = sqrt(g/2h)

Vertical displacement with initial vertical velocity v0 is:

y = v0 t + 1/2 g t^2

y = 1/2 a t^2 only

y = v0 t

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Motion Mastery: Accelerated & Projectile Quiz

Froggy Jumps

Sobre esta actividad

Creada por

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Motion Mastery: Accelerated & Projectile QuizVersión en línea

por Lyra Camile Gacayan

Which equation gives vertical displacement under constant acceleration?

In free fall near Earth, the acceleration is approximately:

Ideal projectile with no air resistance has horizontal acceleration:

Time to return to launch height for vertical throw with speed u is:

In horizontal projectile motion with no air, which is true?

Vertical velocity under constant acceleration is given by:

For a dropped object, speed after t seconds is:

From a height, horizontal launch: which is true?

Vertical time of flight from height h (drop) is:

Vertical displacement with initial vertical velocity v0 is:

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