Icon Crear Crear

Mastering SQL Aggregation Problems

Completar Frases

Drills to master SQL aggregation problems

Descarga la versión para jugar en papel

0 veces realizada

Creada por

Estados Unidos

Top 10 resultados

Todavía no hay resultados para este juego. ¡Sé el primero en aparecer en el ranking! para identificarte.
Crea tu propio juego gratis desde nuestro creador de juegos
Compite contra tus amigos para ver quien consigue la mejor puntuación en esta actividad

Top juegos

  1. tiempo
    puntuacion
  1. tiempo
    puntuacion
tiempo
puntuacion
tiempo
puntuacion
 
game-icon

Completar Frases

Mastering SQL Aggregation ProblemsVersión en línea

Drills to master SQL aggregation problems

por Good Sam
1

FROM sales amount SUM SELECT AS total_sales

Problem 1 : Total Sales
Question : You have a table sales ( order_id INT , amount DECIMAL ) . Write a SQL query to calculate the total sales amount .

Solution :

( )
;





SELECT SUM ( amount ) AS total_sales
FROM sales ;

Explanation : The SUM ( ) function aggregates the total sales by summing up all the amount values in the sales table .

2

AVG SELECT sales FROM amount AS average_sale_amount

Problem 2 : Average Sales per Order
Question : Calculate the average sales amount per order from the sales table .

Solution :

( )
;





SELECT AVG ( amount ) AS average_sale_amount
FROM sales ;

Explanation : The AVG ( ) function calculates the average amount of sales by dividing the total sum of the amount column by the count of rows ( i . e . , number of orders ) .

3

product_id DISTINCT COUNT AS SELECT distinct_products order_details FROM

Problem 3 : Count of Distinct Products Sold
Question : Given a table order_details ( order_id INT , product_id INT ) , find the number of distinct products sold .

Solution :

( )
;






SELECT COUNT ( DISTINCT product_id ) AS distinct_products
FROM order_details ;

Explanation : COUNT ( DISTINCT product_id ) counts the unique product IDs in the order_details table , ignoring duplicates .

4

MIN AS MAX min_sale amount max_sale sales FROM SELECT AS amount

Problem 4 : Maximum and Minimum Sale
Question : Find both the largest and smallest sale amounts from the sales table .

Solution :

( ) , ( )
;






SELECT MAX ( amount ) AS max_sale , MIN ( amount ) AS min_sale
FROM sales ;

Explanation : The MAX ( ) and MIN ( ) functions are used to find the highest and lowest values in the amount column of the sales table .

5

AS sale_date MONTH sale_date MONTH sale_year FROM total_sales sales EXTRACT sale_date FROM AS SELECT BY amount sale_month FROM SUM GROUP EXTRACT EXTRACT sale_month AS YEAR ORDER sale_date YEAR BY FROM FROM EXTRACT sale_year

Problem 5 : Grouped Sales by Month
Question : Assuming a table sales ( order_id INT , amount DECIMAL , sale_date DATE ) , calculate total sales for each month .

Solution :

( ) ,
( ) ,
( )

( ) , ( )
, ;











SELECT EXTRACT ( YEAR FROM sale_date ) AS sale_year ,
EXTRACT ( MONTH FROM sale_date ) AS sale_month ,
SUM ( amount ) AS total_sales
FROM sales
GROUP BY EXTRACT ( YEAR FROM sale_date ) , EXTRACT ( MONTH FROM sale_date )
ORDER BY sale_year , sale_month ;

Explanation : The SUM ( ) function is used to aggregate sales per month , grouped by year and month extracted from sale_date . The GROUP BY clause groups the data into sets that share the same year and month so that SUM ( ) can compute totals for each group .