-x< 1
5x – 3 ≥ 12
5x – 3 = 12
π x + 4 π = π
2 x – 11 = – 9
– 4x – 15 > – 2x – 11
– πx + 4π < π
...
5x - 10 = 5(x - 2)
V = ∅
V = [3, +∞[
V = ]-∞, -2]
V = {3}
V = ]3, +∞[
V = {-3}
V = ]-1, +∞[
V = {1}
V = |R
