a (b + c) = (b + c) a = ab + ac
2 + (-2) = -2 + 2 = 0
(6)(1) = 6
1((2)(3) = ((1)(2))3
(2) (3) = (3) (2)
(1/a)a = 1
a + (b + c) = (a + b) + c
2 + 3 = 3 + 2
a + b = b + a
(1/111)111 = 1
2 + 0 = 0 + 2 = 2
a + 0 = 0 + a = a
(a) 1= 1 (a) = a
a(bc) = (ab)c
ab = ba
1 + (2 + 3) = (1 + 2) + 3
11 (1 + 3) = (1 + 3) 11 = 11(1) + 11(3)
a + (–a) = –a + a = 0