Función Inversa

f(x)=(8x+3)/(x-2)

f(x)= 1/(1+x)

f(x)=1/x

f(x)=x/2

f(x)= (2x-3)/4

f(x)=x+2

f(x)=2x

f(x)=2x +1

f(x)=2x+3/4

f(x)=3x+2/4

y=(4x+3)/2

Y=1/x

y= x/2

y=x/3 -1/6

y=x-2

y=(4x-3)/2

y=2x

y=1/x-1

y=1/2x-1/2

y= (2x+3)/(x-1)